How much would a 50 kg person weigh on the moon?

How much would a 50 kg person weigh on the moon?

Answer: The weight of an object on the moon is 1/6th of that of its weight on earth, since the mass of the moon is a lot less than that of earth. So, the weight of an object of mass 50 kg would be 500 N (taking g = 10 m/s) and on the moon would be 83.3 N (500 6). So, the weight would always be less on the moon.

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How much would a 100 pound person weigh on the moon?

Your weight on the Moon is 16.5% what you would experience on Earth. In other words, if you weighed 100 lbs on Earth, you would weigh a mere 16.5 lbs on the Moon.

How much would a 150 kg object weigh on the moon?

Weight on the moon =150×1/6=25 kg.

How much would 150g be on the moon?

IEEE on Twitter: “If you weigh 150 lbs on Earth, your moon weight would be 24.75 lbs.

How much would a 70 kg man on the moon?

How much would a 70kg man weigh on the moon? What would be his mass on the earth and on the moon? (Acceleration due to gravity on moon=1.63m/s2). First we calculate the weight of the moon. Thus the man would weigh 114.1 newtons on the moon.

How much would a 70 kg person weigh on moon?

Now the mass of the man will be constant irrespective of whether he is on the Earth or on the moon since mass is an intrinsic property of matter. Hence the mass of man on Earth and the moon will be 70 kg.

How much would a 10 kg man weight on the moon?

Answer: Weight of a 10-kg object on moon is 16.33 N.

How much does 1 kg weight on the moon?

The moon has a smaller gravitational field strength. On the Moon, g = 1.6 N/kg. In other words, a 1 kg mass has a weight on the Moon of 1.6 N.

How much would a 60 kg person weigh on the moon?

Weight on Moon =60÷6=10 kg.

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How much would an 80 kg person weigh on the moon?

The moon’s surface gravity is 0.17 that of Earth (table 9-1), so 80 kg weighs 133 n on the moon.

How much would 30 kg weight on the moon?

Weight of the body on the moon = Mass of the body×gravitational acceleration on the moon=30×1. 62=48 N.

Why does a man weighing 90 kg weight only 15 kg on the moon?

Physics tells us that weights of an object on the moon are proportional to its weight on Earth. Suppose a 90 kg man weighs 15kg on the moon. What will be a 60 kg woman weigh on the moon? The average weight of 15 men is increased by 1.6 kg when one of the man, who weights 42 kg is replaced by a new man.

How much would 40 kg weight on the moon?

On the moon that 40 kg child would have a weight of 6.64 Newtons (kg multiplied by gravity) because the moon’s gravity is 1/6th of the Earth’s gravity.

How much would 100 kg be on the moon?

Your weight on the Moon is 16.5% what you would experience on Earth. In other words, if you weighed 100 kg on Earth, you would weigh a mere 16.5 kg on the Moon. For you imperial folks, imagine you tipped the scales at 200 pounds.

How much would a 90 kg man weight on the moon?

A man on the moon with a mass of 90 kilograms weighs 146 newtons.

What is the weight of a 75 kg person on Earth?

Pound (lbs) is an international term used to define the weight or mass of an object. Let’s convert 75 kg into lbs. We know that 1 kg = 2.205 lbs (approx.) Thus, The weight of a 75-kg person in lbs is 165.375 lbs.

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What is the weight of a 70 kg person on Earth?

How much does a 70 kg person weigh on Earth? Answer: Weight on Earth: 686 N.

How much would a 78 kg man weight on the moon?

The correct answer is 127.14 N.

What is the weight of a 55kg person on the moon?

Therefore, the woman’s weight while standing on the moon is 89 N .

What is the weight of a 50kg person on Earth?

This equation can also be written as: Near the Earth’s surface the acceleration due to gravity of an object equals 9.8 m/s2, so if you know the mass of an object, you can calculate its weight as: So if the mass of an object is 50kg then its weight is 490N (50kg x 9.8m/s​2​= 490N; a kg x m/s​2​ is a N).

What is the weight of 50 kg mass?

Therefore the weight of an object with a mass of 50kg is 490 N (Newtons).

What would 60kg man weigh on moon?

Weight on Moon =60÷6=10 kg.